Which is a characteristic of the line that passes through the points (6, 10) and (12, 7)? The slope is mc015-1.jpg. The slope is mc015-2.jpg. The y-intercept is 7. The y-intercept is 13.
Accepted Solution
A:
Answer: slope of the line is -0.5 y-intercept is 13
Explanation: The general formula of the linear equation is: y = mx + cΒ where m is the slope and c is the y-intercept
1- getting the slope: We are given the two points: (6,10) representing (x1 , y1) (12,7) representing (x2 , y2) The slope of the line will be calculated as follows: m = (y2-y1) / (x2-x1) = (7-10) / (12-6) = -3/6 = -0.5 The equation of the line now becomes: y = -0.5x + c
2- getting the value of the y-intercept: To get the value of the y-intercept (c), we will use any of the given points, substitute in the equation of the line and solve for c. I will use the point (6,10) as follows: y = -0.5x + c 10 = -0.5(6) + c 10 = -3 + c c = 13
Based on the above, the equation of the line would be: y = -0.5x + 13