MATH SOLVE

4 months ago

Q:
# One car rental company charges $30 per day plus $0.25 per mile driven. a car company charges $40 per day plus $0.10 per mile driven. how many miles must you drive for a one-day rental at the second company to be less expensive than the same rental at the first company? write an inequality to solve.

Accepted Solution

A:

Rewrite the question into equations:

let's say x is the miles you drive for a day

the first company's rental charge= $30+$0.25x

the second company's rental charge= $40+$0.10x

Calculate what the x is when two equations are equal to each other:

$30+$0.25x=$40+$0.10x

$0.25x-$0.10x=$40-$30

$0.15x=$10

x=$10/$0.15

x=66.667 miles

at least 66.667 miles. I am not sure though. I'm a little bit tired today, so you might want to check it yourself.

let's say x is the miles you drive for a day

the first company's rental charge= $30+$0.25x

the second company's rental charge= $40+$0.10x

Calculate what the x is when two equations are equal to each other:

$30+$0.25x=$40+$0.10x

$0.25x-$0.10x=$40-$30

$0.15x=$10

x=$10/$0.15

x=66.667 miles

at least 66.667 miles. I am not sure though. I'm a little bit tired today, so you might want to check it yourself.