MATH SOLVE

4 months ago

Q:
# Find the dimensions of the box described.The length is twice as long as the width. The height is 4 inches greater than the width. The volume is 720 cubic inches.Find the width and the height?can someone please help :)

Accepted Solution

A:

Answer:dimensions are L = 12, W = 6, H = 10Step-by-step explanation:so we have a box where length is 2x widthget our first equationL = 2wheight is 4 inches + width so the 2nd equation isH = W + 4Volume is 720 inches cube, the formula for volume is L * H * Wso We substitute the equations in the formula2W * (W + 4) * W = 720we get (2W^2 + 8W) * W = 720keep expanding to get 2W^3 + 8W^2 = 720bring the 720 on left side2W^3 + 8W^2 - 720 = 0using calculator we get W = 6substitute it into the equation of H = W + 4H is 10and lastly, L = 2Wso L = 12and there you have it, hope this helped